Python - How To Browse Image File And Display It In Python Tkinter

Python - How To Browse Image File And Display It Into Label Using Python Tkinter 

In this Python Tutorial we will see How To Load A Picture To A Label using filedialog and  askopenfilename In Python Tkinter using VsCode .

Project Source Code:

import tkinter as tk

from tkinter import *

from tkinter import filedialog

from PIL import ImageTk, Image

root = Tk()

frame = tk.Frame(root, bg='#45aaf2')

lbl_pic_path = tk.Label(frame, text='Image Path:', padx=25, pady=25,

font=('verdana',16), bg='#45aaf2')

lbl_show_pic = tk.Label(frame, bg='#45aaf2')

entry_pic_path = tk.Entry(frame, font=('verdana',16))

btn_browse = tk.Button(frame, text='Select Image',bg='grey', fg='#ffffff',

font=('verdana',16))

def selectPic():

global img

filename = filedialog.askopenfilename(initialdir="/images", title="Select Image",

filetypes=(("png images","*.png"),("jpg images","*.jpg")))

img = Image.open(filename)

img = img.resize((200,200), Image.ANTIALIAS)

img = ImageTk.PhotoImage(img)

lbl_show_pic['image'] = img

entry_pic_path.insert(0, filename)

btn_browse['command'] = selectPic

frame.pack()

lbl_pic_path.grid(row=0, column=0)

entry_pic_path.grid(row=0, column=1, padx=(0,20))

lbl_show_pic.grid(row=1, column=0, columnspan="2")

btn_browse.grid(row=2, column=0, columnspan="2", padx=10, pady=10)

root.mainloop()

/////OUTPUT:
  




 
   
 

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